Heat Transfer and Calorimetry Physics Simulation
This interactive 3D physics simulation demonstrates heat transfer between a hot liquid and a cooler metal object. Students can change the material, mass, initial temperature, and specific heat values, then observe the metal being lowered into the liquid and calculate the final equilibrium temperature.
Heat Transfer and Thermal Equilibrium
When two objects at different temperatures are placed in thermal contact, heat flows from the hotter object to the cooler object. In an ideal isolated system, this continues until both objects reach the same final temperature.
Q = mcΔT
Here, Q is heat transferred, m is mass, c is specific heat capacity, and ΔT is the temperature change.
Conservation of Energy in Calorimetry
If no energy is lost to the surroundings, the heat lost by the hot liquid equals the heat gained by the cooler metal:
m₁c₁(Tf − T₁) = −m₂c₂(Tf − T₂)
Solving for the final temperature gives:
Tf = (m₁c₁T₁ + m₂c₂T₂) / (m₁c₁ + m₂c₂)
What Students Learn
- Heat flows because of a temperature difference.
- Objects reach thermal equilibrium when their temperatures become equal.
- Specific heat determines how strongly a material's temperature changes for a given heat transfer.
- Mass affects the amount of energy required to change temperature.
- Conservation of energy can be used to calculate the final equilibrium temperature.
How to Use This Simulation
- Select a metal and a hot liquid.
- Adjust their masses and initial temperatures.
- Click Start to lower the metal into the liquid.
- Observe the liquid level and the final equilibrium temperature.
- Try the unknown materials and use the calorimetry equation to investigate their specific heat values.
Related 3JCN Physics Simulations