Heat Transfer

Calorimetry, specific heat, and thermal equilibrium

Metal

Specific heat = 0.385 J/g·°C
g
300 g700 g
°C
10 °C30 °C
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Final Equilibrium Temperature

Hot Liquid

Specific heat = 4.184 J/g·°C
g
1200 g2000 g
°C
60 °C160 °C
Energy Conservation
Qliquid + Qmetal = 0
m₁c₁(Tf − T₁) = −m₂c₂(Tf − T₂)
Heat flows from the hotter liquid to the cooler metal until both reach the same temperature.

Heat Transfer and Calorimetry Physics Simulation

This interactive 3D physics simulation demonstrates heat transfer between a hot liquid and a cooler metal object. Students can change the material, mass, initial temperature, and specific heat values, then observe the metal being lowered into the liquid and calculate the final equilibrium temperature.

Heat Transfer and Thermal Equilibrium

When two objects at different temperatures are placed in thermal contact, heat flows from the hotter object to the cooler object. In an ideal isolated system, this continues until both objects reach the same final temperature.

Q = mcΔT

Here, Q is heat transferred, m is mass, c is specific heat capacity, and ΔT is the temperature change.

Conservation of Energy in Calorimetry

If no energy is lost to the surroundings, the heat lost by the hot liquid equals the heat gained by the cooler metal:

m₁c₁(Tf − T₁) = −m₂c₂(Tf − T₂)

Solving for the final temperature gives:

Tf = (m₁c₁T₁ + m₂c₂T₂) / (m₁c₁ + m₂c₂)

What Students Learn

How to Use This Simulation

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